[Solved] Two 1 Coulomb charges are kept at 1m distance in air medium. Force of attraction or repulsion between them will be ________

Two 1 Coulomb charges are kept at 1m distance in air medium. Force of attraction or repulsion between them will be ________

a) 9*109 N
b) 1 dyne
c) 1 N
d) 3*103 N

Answer: a
Explanation: According to Coulomb’s Law, F=1/4πεo∗q1q2/r2. And 1/4πεo = 9*109N in the SI system. In this case, q1=q2=1C and r=1m. Now substituting the values we get F=9*109N. Similarly, the electric field at a distance of 1m from a 1C charge is 9*109N/C.

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